JEE MAIN - Physics (2024 - 4th April Evening Shift - No. 26)
Mercury is filled in a tube of radius $$2 \mathrm{~cm}$$ up to a height of $$30 \mathrm{~cm}$$. The force exerted by mercury on the bottom of the tube is _________ N.
(Given, atmospheric pressure $$=10^5 \mathrm{~Nm}^{-2}$$, density of mercury $$=1.36 \times 10^4 \mathrm{~kg} \mathrm{~m}^{-3}, \mathrm{~g}=10 \mathrm{~m} \mathrm{~s}^{-2}, \pi=\frac{22}{7})$$
پاسخ دهید
177
توضیح
$$\begin{aligned}
F & =\left(p_0+\rho g h\right) A \\
& =\left(10^5+1.36 \times 10^4 \times 10 \times \frac{3}{10}\right) \frac{22}{7}\left(\frac{2}{100}\right)^2 \\
& =177 \mathrm{~N}
\end{aligned}$$